A solution is prepared by dissolving 0.300 moles of solute in 3.00 liters of solution. What is the molarity?

A solution is prepared by dissolving 0.300 moles of solute in 3.00 liters of solution. What is the molarity?

• A. 0.300 M
• B. 1.00 M
• C. 3.00 M
• D. 0.100 M

Answer: (D)

Molarity is the amount of solute per liter of solution. Here, you have 0.300 moles in 3.00 liters, so M = n/V = 0.300 / 3.00 = 0.100 M. This uses three significant figures, so the result is 0.100 M. If the volume were different, the molarity would change accordingly: 0.300 moles in 1.00 L would be 0.300 M; in 0.300 L it would be 1.00 M; in 0.100 L it would be 3.00 M.

Molarity is the amount of solute per liter of solution. Here, you have 0.300 moles in 3.00 liters, so M = n/V = 0.300 / 3.00 = 0.100 M. This uses three significant figures, so the result is 0.100 M.

If the volume were different, the molarity would change accordingly: 0.300 moles in 1.00 L would be 0.300 M; in 0.300 L it would be 1.00 M; in 0.100 L it would be 3.00 M.